(x^2+3y-3)-(-2x^2+3y-1)=0

Solution for (x^2+3y-3)-(-2x^2+3y-1)=0 equation:

Simplifying
(x2 + 3y + -3) + -1(-2x2 + 3y + -1) = 0

Reorder the terms:
(-3 + x2 + 3y) + -1(-2x2 + 3y + -1) = 0

Remove parenthesis around (-3 + x2 + 3y)
-3 + x2 + 3y + -1(-2x2 + 3y + -1) = 0

Reorder the terms:
-3 + x2 + 3y + -1(-1 + -2x2 + 3y) = 0
-3 + x2 + 3y + (-1 * -1 + -2x2 * -1 + 3y * -1) = 0
-3 + x2 + 3y + (1 + 2x2 + -3y) = 0

Reorder the terms:
-3 + 1 + x2 + 2x2 + 3y + -3y = 0

Combine like terms: -3 + 1 = -2
-2 + x2 + 2x2 + 3y + -3y = 0

Combine like terms: x2 + 2x2 = 3x2
-2 + 3x2 + 3y + -3y = 0

Combine like terms: 3y + -3y = 0
-2 + 3x2 + 0 = 0
-2 + 3x2 = 0

Solving
-2 + 3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 3x2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 3x2 = 0 + 2
3x2 = 0 + 2

Combine like terms: 0 + 2 = 2
3x2 = 2

Divide each side by '3'.
x2 = 0.6666666667

Simplifying
x2 = 0.6666666667

Take the square root of each side:
x = {-0.816496581, 0.816496581}